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The area of rhombus is $16 c m^{2}$ and the length of one of its diagonal is 4cm, then the length of other diagonal is

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8cm

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answer is A.

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Detailed Solution

$d_{1} = 4 c m$

$d_{2} =___$

Area of rhombus $= \frac{1}{2} \times d_{1} \times d_{2} c m^{2}$

$16 = \frac{1}{2} \times 4 \times d_{2}$

$16 = 2 d_{2}$

$∴ d_{2} = \frac{16}{2} = 8 c m$

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