The area of the plates of a one farad parallel plate capacitor, if separation between plates is 1 mm and plates are in vacuum, is $1.13 \times 10^{p} m^{2}$ . Find the value of $p$ .

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Detailed Solution

$\begin{array}{l} For a parallel plate capacitor C = \frac{ε_{0} A}{d} \\ ∴ A = \frac{Cd}{ε_{0}} = \frac{1 \times 10^{- 3}}{8.85 \times 10^{- 12}} = 1.13 \times 10^{8} m^{2} \end{array}$

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