The area of the quadrilateral with vertices at $(2, -1), (4, 3), (-1, 2)$ and $(-3, -2)$ is

Let A=(2, -1), B=(4, 3), C=(-1, 2), D=(-3, -2) are vertices of quadrilateral.

$$\begin{gathered} \therefore \mathrm{Area}=\frac{1}{2}\overline{)\begin{array}{c}{\mathrm{x}}_1-{\mathrm{x}}_3\\ {\mathrm{x}}_2-{\mathrm{x}}_4\end{array}\begin{array}{c}\mathrm{X}\end{array}}\overline{)\begin{array}{c}{\mathrm{y}}_1-{\mathrm{y}}_3\\ {\mathrm{y}}_2-{\mathrm{y}}_4\end{array}} \\ =\frac{1}{2}\overline{)\begin{array}{c}3\\ 7\end{array}\begin{array}{c}\mathrm{X}\end{array}}\overline{)\begin{array}{c}-3\\ 5\end{array}} \\ =\frac{1}{2}\left|15+21\right| \\ =\frac{36}{2} \\ =18 \end{gathered}$$