The area of the region bounded by the line y =4 and curve y =x² is

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$\frac{32}{3} square units$

0 square unit

1 square unit

32 square unit

answer is A.

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Detailed Solution

y=x²

$x = \sqrt{y}$
Question Image

$\begin{array}{l} ∴ Area = 2 \int_{0}^{4} \sqrt{y} d y \\ = 2 {[\frac{2}{3} y^{\frac{3}{2}}]}_{0}^{4} = \frac{4}{3} [8 - 0] = \frac{32}{3} square units \end{array}$

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