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The area of the region bounded by the lines $y = | x - 1 | and y = 3 - | x |$ is

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answer is C.

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Detailed Solution

$y = | x - 1 |$

$\Rightarrow y = x - 1, x \geq 1 and y = 1 - x, x < 1$

$y = 3 - | x | \Rightarrow y = 3 - x, x \geq 0, y = 3 + x, x < 0$

The four lines form a rectangle

$A B = \sqrt{2}, B C = \sqrt{8} . Area = 4$

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