The area of the region bounded by x = –1, x = 2, y = x2 + 1 and y = 2x–2 is ___ sq.units

A=A1+A2=∫−12 x2+1−(2x−2)dx=∫−12 x2−2x+3dxA=x33-x2+3x-12=83-4+6--13-1-3=9

The area of the region bounded by x = –1, x = 2, y = x2 + 1 and y = 2x–2 is ___ sq.units

A=A1+A2=∫−12 x2+1−(2x−2)dx=∫−12 x2−2x+3dxA=x33-x2+3x-12=83-4+6--13-1-3=9

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The area of the region bounded by x = –1, x = 2, y = x² + 1 and y = 2x–2 is ___ sq.units

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$\begin{matrix} A = A_{1} + A_{2} = \int_{- 1}^{2} [(x^{2} + 1) - (2 x - 2)] d x \\ = \int_{- 1}^{2} (x^{2} - 2 x + 3) d x \end{matrix}$

$A = {(\frac{x^{3}}{3} - x^{2} + 3 x)}_{- 1}^{2} = (\frac{8}{3} - 4 + 6) - (\frac{- 1}{3} - 1 - 3) = 9$

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The area of the region bounded by x = –1, x = 2, y = x2 + 1 and y = 2x–2 is ___ sq.units

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The area of the region bounded by x = –1, x = 2, y = x² + 1 and y = 2x–2 is ___ sq.units