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The area of the square formed by the lines $6 x^{2} - 5 x y - 6 y^{2} = 0$ and $6 x^{2} - 5 x y - 6 y^{2} + x + 5 y - 1 = 0$ in sq. Units is

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$1 / \sqrt{3}$

$4 / \sqrt{13}$

$\sqrt{13}$

$1 / 13$

answer is D.

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Detailed Solution

$\frac{| c |}{2 \sqrt{h^{2} - a b}}$

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