The area of the triangle formed by co-ordinate axes and tangent at vertex to the parabola, whose focus is (3, 4) and tangents are x = 0, y = 0 is …………..sq. units

Locus of the foot of the perpendicular from focus to tangents is tangent at vertex
So tangent at vertex passes through (3,0) & (0, 4)

Tangent vertex equation is $\frac{\mathrm{x}}{3}+\frac{\mathrm{y}}{4}=1$
So area $=\frac{1}{2}\times 3\times 4=6$