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Q.

The area of triangle formed by tangents at the parametric points t1, t 2 and t 3 on y2 = 4ax is kt1−t2t2−t3t3−t1 then K

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a

a22

b

2a2

c

a2

d

4a2

answer is A.

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Detailed Solution

=a22t1−t2t2−t3)t3-t1∴K=a22

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The area of triangle formed by tangents at the parametric points t1, t 2 and t 3 on y2 = 4ax is kt1−t2t2−t3t3−t1 then K