Q.

The area of triangle formed by tangents at the parametric points  t1,t2 and  t3 on y2=4ax  is   kt1t2t1t3t3t1 then K=

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a

a2/2

b

a2

c

2a2

d

4a2

answer is A.

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Detailed Solution

We know that area of the triangle is

a22t1t2t2t3t3t1K=a22

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The area of triangle formed by tangents at the parametric points  t1,t2 and  t3 on y2=4ax  is   kt1−t2t1−t3t3−t1 then K=