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Q.

The areas of three adjacent faces of a rectangular box which meet in a point are known. The product of these areas is equal to _______.


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a

The volume of the box.

b

Twice the volume of the box.

c

The square of the volume of the box.

d

The cube root of the volume of the box. 

answer is C.

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Detailed Solution

We know that a cuboid is a three dimensional object with six rectangular faces joined by 8 vertices. It has three different types of sides called length, breadth and height denoted l, b and h. The amount of space contained by a three dimensional object is measured by the quantity called volume. The amount of space that is occupied by a cuboid is the product of length, breadth and height. Mathematically, volume denoted as V a cuboid is
V=l×b×h=lbh  ......(1)
https://www.vedantu.com/question-sets/269b214b-ea86-4cb5-8a3b-5244c8fdd9746966283203251421759.pngLet us denote the vertices of the cuboid as A, B, C, D, E, F, G, H. We are going to call two rectangular surfaces adjacent when they share a common vertex. We have the rectangular surfaces ABCD, DCFG and ADGH share the common vertex D. Let us assign
AB = HE = GF = CD = l
AD = BC = EF = GH = b
AH = GD = BE = CF = h
We are given the question that the areas of three adjacent faces of a rectangular box which meet in a point are known. The rectangular face is the product of its different sides. So the areas of three adjacent faces are
AreaofABCD=AB×BC=l×b=lb AreaofDCFG=DC×GD=h×l=hl AreaofADGH=GH×GD=l×b=lb  
So the product surface areas of the three adjacent faces is
AreaofABCD×AreaofABCD×AreaofABCD=lb×bh×hl= l 2 b 2 h 2 = (lbh) 2  
We use value for equation (1) and have;
AreaofABCD×AreaofBCD×AreaofABCD= (lbh) 2 = V 2  
The product of these areas is equal to the square of the volume.
 
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