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Q.

The areas of two similar triangles are 121 cm² and 64 cm² respectively. If the median of first triangle is 12.1 cm, then corresponding median of the other is

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a

10cm

b

12cm

c

8.8cm

d

7cm

answer is A.

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Detailed Solution

It is given that the areas of two similar triangles are 121 cm² and 64 cm² respectively.
The ratio of the areas of two similar triangles is equal to the ratio of the squares of the corresponding medians
We can write that,

\frac{area of first triangle}{area of second triangle} = \frac{{(median of first triangle)}^{2}}{{(median of second triangle)}^{2}}

If the median of the first triangle is 12.1, then the corresponding median of the other can be found by substituting the given values in the above equation.

12164 = 12.1 2 x 2 x 2 = 12.1 2 × 64 121 x = 12.1 2 × 64 121 ⇒ 1110 × 8

⇒ 8.8 c m

Hence, the correct option is 1.

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