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Q.

The armature of dc motor has $20 Ω$ resistance. It draws current of 1.5 ampere when run by 220 volts dc supply. The value of back e.m.f. induced in it will be

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a

190 V

b

170 V

c

180 V

d

150 V

answer is D.

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Detailed Solution

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$i = \frac{E - e}{R} \Rightarrow 1.5 = \frac{220 - e}{20} \Rightarrow e = 190 V$

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