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Q.
The atomic mass of carbon (diamond) is 12.01U and density is 2.22 × 103kg m–3, the radius of the carbon atom is
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a
4.25A0
b
2.32A0
c
1.29A0
d
3.52A0
answer is B.
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Detailed Solution
The question asks us to calculate the radius of a carbon atom in diamond, given the following data:
- Atomic mass of carbon: 12.01 U
- Density of carbon (diamond): 2.22 × 103 kg/m3
Step-by-Step Solution
To determine the radius of a carbon atom in diamond, we will use the following relationship:
The volume V of a single carbon atom can be expressed as the volume of a sphere:
V = (4/3)πr³
Where r is the radius of the carbon atom.
1. Calculate the Mass of a Single Carbon Atom
First, we need to calculate the mass of a single carbon atom using the atomic mass of carbon.
The atomic mass of carbon is 12.01 U (unified atomic mass units), where 1 atomic mass unit (1 U) = 1.67 × 10-27 kg.
Thus, the mass of one carbon atom is:
Mass of one carbon atom = 12.01 × 1.67 × 10-27 kg
= 2.00 × 10-26 kg
2. Use the Density to Find Volume
The density formula is:
Density = Mass / Volume
Rearranging the formula to solve for volume:
Volume = Mass / Density
Substitute the known values:
Volume of one carbon atom = (2.00 × 10-26 kg) / (2.22 × 103 kg/m3)
= 9.00 × 10-30 m3
3. Calculate the Radius
Now that we know the volume, we can use the formula for the volume of a sphere:
V = (4/3)πr³
Substitute the value for the volume:
9.00 × 10-30 m3 = (4/3)πr³
Solving for r:
r³ = (3 × 9.00 × 10-30) / (4π)
r³ = 2.14 × 10-30 m3
Taking the cube root:
r ≈ 1.29 × 10-10 m
4. Convert to Angstroms
Finally, to express the radius in more familiar units, we convert from meters to angstroms (1 angstrom = 1 × 10-10 m):
r ≈ 1.29 Å
Conclusion
The radius of a carbon atom in diamond, based on the atomic mass of carbon and the given density, is approximately 1.29 Å (angstroms).
In summary, we used the atomic mass of carbon and its density to calculate the volume of a single atom, and then derived the radius of the atom in the crystalline structure of diamond.