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The atomic weight of two elements A and B are 40 and 80 respectively. If x g of A contains y atoms, how many atoms are present in 2x g of B ?

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$\frac{y}{2}$

$\frac{y}{4}$

answer is C.

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Detailed Solution

	A	B
Atomic mass	40	80
Given weight	x gram	2x gram
No. of mole	$\frac{x}{40}$	$\frac{2 x}{80}$
No. of atom	$\frac{x}{40} \times N_{A}$	$\frac{x}{40} \times N_{A}$

But according to the question $= \frac{x}{40} \times N_{A} = y$

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