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Q.

The average angular velocity of the seconds hand of watch if the seconds hand of a watch completes one revolution in 1 minute is

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a

$\frac{π}{10} {rads}^{- 1}$

b

$\frac{π}{20} {rads}^{- 1}$

c

$\frac{π}{30} {rads}^{- 1}$

d

$\frac{π}{15} {rads}^{- 1}$

answer is C.

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Detailed Solution

$ω_{arg} = \frac{angular displacement}{time} = \frac{2 π^{t}}{Timeperiod} = \frac{2 π^{c}}{60}$ $∵ Time period of seconds hand = 60 s$

$= \frac{π}{30} rad / s$

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