The average degrees for freedom per molecule for a gas are ‘6’. The gas performs 25J of work when it expands at constant pressure. The heat absorbed by gas is

$$\begin{gathered} first law of thermodynamics , heat absorbed=\Delta Q=\Delta U+\Delta W \\ we know change in internal energy \Delta U=n{C}_v\Delta T \\ \Delta U=\frac{f}{2}\times nR\Delta T Where, f=no.of degrees of freedom=6 ( given) \\ \Rightarrow \Delta U=\frac{6}{2}\times nR\Delta T=3nR\Delta T \\ work done at cons\tan t pressure, \Delta W=nR\Delta T=25J \\ heat absorbed=\Delta Q=\Delta U+\Delta W \\ \Rightarrow \Delta Q=4nR\Delta T=4\times 25J \\ \Rightarrow \Delta Q=100J \end{gathered}$$