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Q.

The average degrees of freedom per molecule of a gas are 6. The gas performs 25J of work when expands at constant pressure. The heat absorbed by the gas is

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a

75 J

b

100 J

c

150 J

d

125 J

answer is B.

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Detailed Solution

$γ$ for the gas = $1 + \frac{2}{f} = 1 + \frac{2}{6} = \frac{4}{3}$

Given ,

Work, $W = 25 J = nR △ T$

Heat absorbed by the gas, $Q = {nC}_{P} △ T = n 4 R △ T = 4 \times 25 = 100 J$

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