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The average distance between the earth and moon is 38.6×10⁴ km. The minimum separation between the two points on the surface of the moon that can be resolved by a telescope whose objective lens has a diameter of 5 m with λ = 6000A⁰ is

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5.65 m

28.25 m

11.30 m

56.51 m

answer is D.

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Detailed Solution

$Δ θ c = \frac{1.22 λ}{a} = \frac{1.22 \times 6000 \times 10^{- 10}}{5}$

$Al so θ_{c} = \frac{d}{D} = \frac{d}{38 .6 \times 10^{7}}$

$d = \frac{1.22 \times 6 \times 10^{- 7} \times 38.6 \times 10^{7}}{5} = 56.51 m$

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