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The average kinetic energies of helium (mol.wt.4), methane (mol.wt.16) and sulphurdioxide (mol.wt.64), at certain temperature are respectively x, y and z kJmol^-1. The ratio of x, y and z is

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1 : 1 : 1

1 : 4 : 16

4 : 2 : 1

1 : 2 : 4

answer is C.

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Detailed Solution

Average K.E.= $\frac{3}{2} nRT$

$n_{1} = \frac{4}{4} = 1 n_{2} = \frac{16}{16} = 1 n_{3} = \frac{64}{64} = 1 K . E_{1} : K . E_{2} : K . E_{3} = \frac{3}{2} n_{1} RT : \frac{3}{2} n_{2} RT : \frac{3}{2} n_{3} RT = 1 : 1 : 1$

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