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The average kinetic energy of nitrogen molecules is E, at room temperature. The corresponding value for helium molecules will be: (Relative molecular weight of N₂ and He are 28 and 4)

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E/7

$\frac{3 E}{5}$

answer is D.

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Detailed Solution

$\begin{array}{l} < E > for nitrogen = \frac{5 KT}{2} = E \dots \dots . . (1) \\ < E > for helium = \frac{3}{2} KT = E^{1} \dots \dots (2) ∴ E^{1} = \frac{3 E}{5} \end{array}$

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