Q.

The average (mean) life at a radio nuclide which decays by parallel path is :

Aλ1B      λ1=1.8×102sec1

2Aλ2C        λ2=103sec1

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a

50 sec

b

none of these

c

52.63 sec

d

500 sec

answer is C.

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Detailed Solution

We know about the

λ=λ1+λ2

 then 

=20×103

t1/2=120×103=50sec

The average (mean) life at a radio nuclide which decays by parallel path is  50 sec

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