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Q.

The average molar mass of chloride is $35.5 g m o l^{- 1}$ . The ratio of $^{x} C l t o^{37} C l$ in naturally occurring is 3:1, The value of x is

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a

36

b

34

c

35

d

37

answer is B.

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Detailed Solution

$\begin{matrix} C l^{35} & C l^{37} \\ m o l e f r a c t i o n & x & 1 - x \end{matrix}$

$M_{a v g} = x \times 35 + (1 - x) (37) = 35.5$

$\Rightarrow 35 x + 37 - 37 x = 35.5$

$\begin{array}{l} 2 x = \frac{3}{2} \\ x = \frac{3}{4} \end{array}$

$\frac{C l^{35}}{C l^{37}} = \frac{x}{(1 - x)} = \frac{3 / 4}{1 / 4} = 3 : 1$

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