The average molecular mass of a mixture of gas containing nitrogen and carbon dioxide is 36. The mixture contain 280 g of nitrogen, therefore, the amount of CO₂ present in the mixture is

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220g

44 g

440 g

880 g

answer is A.

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Detailed Solution

Let amount of CO₂present = x g

$36 = \frac{\frac{280}{28} \times 28 + \frac{x}{44} \times 44}{\frac{280}{28} + \frac{x}{44}}$

$\begin{array}{l} 36 = \frac{280 + x}{10 + x / 44} = \frac{(280 + x) \times 44}{440 + x} \\ or 15840 + 36 x = 12320 + 44 x \\ or 8 x = 3520 \\ x = \frac{3520}{8} = 440 g \end{array}$

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