The average of 20 numbers is zero . Of them , at the most , how many may be greater than zero ?

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answer is D.

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Detailed Solution

Concept-As we know, the average is equal to the sum of the numbers where the sum of the number of problems is equal to 0. Therefore, from here on, the sum of the numbers is equal to 0. So this is possible because the sum of the 12 numbers is c and the remainder 8 is the sum -c, and the sum of the 20 numbers is 0. In the question, there is the maximum positive number possible.
Let the 20 numbers be

Given that the average of 20 numbers is zero.
Therefore,

Therefore, at most 19 numbers can be greater than zero.
Hence, the correct option is 4.

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