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Q.

The average of six numbers is 3.95. The average of two of
them is 3.4, while the average of the other two is 3.85.
What is the average of the remaining two numbers?

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a

4.5

b

4.6

c

4.7

d

4.8

answer is B.

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Detailed Solution

Sum of the remaining two numbers

$\begin{array}{l} = (3.95 \times 6) - [(3.4 \times 2) + (3.85 \times 2)] \\ = 23.70 - (6.8 + 7.7) = 23.70 - 14.5 = 9.20 \end{array}$

$∴$ Required average $= (\frac{9.2}{2}) = 4.6$

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