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Q.

The average radius of an air cored toroid is 0.1 m and it has 500 turns. If it carries 0.5 ampere current, then the magnetic field inside it is :

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a

$5 \times 10^{- 4} tesla$

b

$5 \times 10^{- 3} tesla$

c

$5 \times 10^{- 2} tesla$

d

$2 \times 10^{- 3} tesla$

answer is A.

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Detailed Solution

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$magnetic field due to a toroid = \frac{μ_{0} NI}{2 πR},$

$where N is the total no of turns$

$and R is the mean radius$

$B = \frac{4 π \times 10^{- 7} \times 500 \times 0.5}{2 π \times 0.1} = 5 \times 10^{- 4} T$

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The average radius of an air cored toroid is 0.1 m and it has 500 turns. If it carries 0.5 ampere current, then the magnetic field inside it is :