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Q.

The average resisting force that must act on a 5kg mass to reduce its speed from $65 {cms}^{- 1} to 15 {cms}^{- 1}$ in 0.2s is

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a

25 N

b

50 N

c

12.5 N

d

100 N

answer is A.

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Detailed Solution

F = m (\frac{v - u}{t})

$= 5 (\frac{0.15 - 0.65}{0.2})$

$= - 5 (\frac{0.5}{0.2})$

$F = - 12.5 N$

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