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The average resisting force that must act on a 5 kg mass to reduce its speed from 65 cm/sec to 15 cm/sec in 0.2 sec is

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12.5 N

25 N

50 N

100 N

answer is A.

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Detailed Solution

$F o r c e = \frac{C h a n g e i n m o m e n t u m}{T i m e t a k e n}$

$\frac{p_{j} - p_{i}}{t i m e}$

$= \frac{\frac{5 \times 65}{100} - \frac{5 (15)}{100}}{0.2}$

$= \frac{3.25 - 0.75}{0.2}$

$= \frac{2.5 (10)}{2} = 12.5 N$

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