The average speed of blood in the artery (diameter = 2mm) during the resting part of heart's cycle is about 30 cm s^-1. Density of blood $$\begin{gathered} 1.05\times {10}^3 \mathrm{Kg} {\mathrm{m}}^{-3}. \\ \mathrm{\eta }=2.7\times {10}^{-3}\mathrm{Pa}-\mathrm{s} \end{gathered}$$

The characteristic of flow is

Given,

$\mathrm{diameter} \mathrm{d}=2\mathrm{mm}, \mathrm{density} \mathrm{\rho }=1.05\times {10}^3{\mathrm{Kgm}}^{-3}$

$\mathrm{\eta }=2.7\times {10}^{-3} \mathrm{and} \mathrm{average} \mathrm{speed}=30\mathrm{cm}/\mathrm{s}$

we can know the characteristic of the flow by reynold's number,

$\mathrm{R}=\frac{\mathrm{v\rho d}}{\mathrm{\eta }}=\frac{30\times {10}^{-2}\times 1.05\times {10}^3\times 2\times {10}^{-2}}{2.7\times {10}^{-3}}=3038$

$\because \mathrm{R}>1500 \mathrm{turbulent} \mathrm{flow}$

Hence the correct answer is turbulent.