The average temperature of the town in the first four days of a month was 58 degrees. The average for the second, third, fourth and fifth days was 60 degrees. If the temperatures of the first and fifth days were in the ratio 7 : 8, then what is the temperature on the fifth day? 

Given that average temperature of the town in the first four days of a month was 58 degrees and average for the second, third, fourth and fifth days was 60 degrees

$\begin{array}{rcl}\frac{a+b+c+d}{4}& =& 58\\ a+b+c+d& =& 4\left(58\right)\\ a+b+c+d& =& 232\end{array}$

Given 

$$\begin{gathered} b+c+d+e=4\left(60\right) \\ b+c+d+e=240 \\ b+c+d=240-e \end{gathered}$$

$\begin{array}{rcl}a+240-e& =& 232\\ a-e& =& -8\\ e-a& =& 8\end{array}$

Given that the temperatures of the first and fifth days were in the ratio 7 : 8

$\begin{array}{rcl}8x-7x& =& 8\\ x& =& 8\end{array}$

Therefore, the temperature in fifth day is $8\left(8\right)=\boxed{64 years}$