The average thermal energy of a molecule of a diatomic gas is (temperature of gas is T and Boltzmann's constant is K).

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$\frac{5 K T}{2}$

$\frac{3 K T}{2}$

$\frac{7 K T}{2}$

$\frac{9 K T}{2}$

answer is A.

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Detailed Solution

By law of equipartition of energy, average energy possessed by an ideal gas molecule for each degree of freedom is $K T / 2$ . Number of degrees of freedom of a diatomic gas molecule is 5.

Hence average energy of a molecule is $5 K T / 2$ .

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