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Q.

The average value of electric energy density in an electromagnetic wave is (E₀ is peak value)

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a

$ε_{0} E_{0}^{2}$

b

$\frac{1}{4} ε_{0} E_{0}^{2}$

c

$\frac{E_{0}^{2}}{2 ε_{0}}$

d

$\frac{1}{2} ε_{0} E_{0}^{2}$

answer is D.

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Detailed Solution

detailed_solution_thumbnail

Electric energy density, $u_{e} = \frac{1}{2} ε_{0} E_{rms}^{2}$

$E_{rms} = \frac{E_{0}}{\sqrt{2}}$ $∴ u_{e} = \frac{1}{4} ε_{0} E_{0}^{2}$

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