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The axes of the polariser and analyser are inclined to each other at 60°. If the amplitude of polarised light emergent through analyser is A . The amplitude of unpolarised light incident on polariser is

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$\frac{A}{2}$

$A$

$2 A$

$2 \sqrt{2} A$

answer is D.

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Detailed Solution

$A = \frac{A_{0}}{\sqrt{2}} \cos ϕ = \frac{A_{0}}{\sqrt{2}} \cos 60^{\circ} \Rightarrow A_{0} = 2 \sqrt{2} A$

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