Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The axis of a parabola is along the line y = x and the distance of its vertex and focus from the origin are 2 and 22 , respectively. If vertex and focus both lie in the first quadrant, then the equation of the parabola is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

(x+y)2=(xy2)

b

(xy)2=4(x+y2)

c

(xy)2=8(x+y2)

d

(xy)2=(x+y2)

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Axis of parabola is y = x
Since vertex is at a  distance of 2 from (0, 0), vertex is
A(1, 1), also, focus is at a  distance of  22 from (0, 0),focus is S(2, 2). Distance SA =2 .
So, directrix is at  a distance 2 from origin, which is x + y = 0. Hence equation of the parabola is (x2)2+(y2)2=|x+y|2 (SP=PM)
 x2+y22xy=8(x+y2) ⇒ (xy)2=8(x+y2)

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon