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The azeotropic mixture of water (b.p. $100 ° C$ ) and HCI (b.p. $85 ° C$ ) boils at $108.5 ° C .$ When this mixture is distilled it is possible to obtain

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Pure $HCI$

Pure water

Pure water as well as pure $HCl$

Neither $HCl$ nor $H_{2} O$ in their pure states

answer is D.

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Detailed Solution

Azeotropic mixture is constant boiling mixture, it is not possible to separate the components of azeotropic mixture by boiling.

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