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Q.

The barrier potential in an ideal p-n junction diode is 0.3 volts. The current required is 6 mA. If a resistance of 200 Ω is connected in series with the junction diode, then the emf of the cell required for use in the circuit is 
 

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a

0.9 V 
 

b

1.5 V 
 

c

1.2 V 
 

d

0.3 V 
 

answer is D.

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Detailed Solution

Given,

VD=0.3V ; I=6mA=0.006A;R=200Ω

We know that 

E-VD=IR ;E=IR+VD; 

E=(0.006×200)+0.3

E=1.2+0.3 E=1.5V

Hence the correct answer is 1.5V.

 

 

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