The base of right pyramid is a square of side 10 cm. if the height of the pyramid is 12 cm, then its

Base of right pyramid is square of side (s) = 10 cm 

Height of pyramid = 12 cm

$$\begin{gathered} slant height =\sqrt{h^2+\left(\frac{r^2}{2}\right)} = \sqrt{{12}^2+5^2 } = 13 cm \\ L.S.A =\frac{1}{2}\times perimeter of base \times slant height =\frac{1}{2}\times \left(4\times 10\right)\times 13 \\ = 260 c{m}^2 \\ TSA = LSA + Area of base = 260\hspace{0.17em}+ {10}^2 = 360 c{m}^2 \\ Volume = \frac{1}{3}\times area of base \times height =\frac{1}{3}\times \left(10\times 10\right)\times 12=400 c{m}^2 \end{gathered}$$