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The base radius and height of a cone is 7 cm and 24 cm respectively. If the cone is cut parallel to its base. If the volume of this frustum is 503 cm³ find the volume of smaller cone?

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729 cm³

729 cm²

1232 cm³

None of these

answer is B.

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Detailed Solution

Radius of the cone $r = 7 c m$ , height of the cone $h = 24 c m$

Volume of the cone $= \frac{1}{3} π r^{2} h = \frac{1}{3} \times \frac{22}{7} \times 7^{2} \times 24 = 1232 c m^{3}$

Volume of smaller cone after removed frustum $= 1232 - 503 = 729 c m^{3}$

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