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Q.

The BEA for deuteron and a-particle are X1 and X2 respectively. The energy released in the reaction 1H2 + 1H22He4 is

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a

X2 - X1

b

2(X2 - X1)

c

4(X2 - X1)

d

8(X2 - X1)

answer is C.

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Detailed Solution

Energy E = 4 X2 - 2 × 2 X1
= 4X2 - 4X1
= 4(X2 - X1)

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