The bike covers a distance of 80 m, when it changes its speed from $30 \mathrm{km}/\mathrm{hr}$ to $70 \mathrm{km}/\mathrm{hr}$. What is the acceleration of the bike?

Here u = 30 km/h = $30\times \frac{5}{18}$= 8.3 m/s

v = 70 km/h = $70\times \frac{5}{18}$= 19.44 m/s

s = 80 m

From 3rd equation of motion,

2as =v² - u²

$\mathrm{a}=\frac{{\mathrm{v}}^2-{\mathrm{u}}^2}{2\mathrm{s}}$

$a=\frac{19.{44}^2-8.3^2}{2\times 80}$

a = 1.93 m/s²