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Q.

The binding energies per nucleon are 5.3 MeV, 6.2 MeV and 7.4 MeV for the nuclei with mass numbers 3,4 and 5 respectively. If one nucleus of mass number 3 combines with one nucleus of mass number 5 to give two nuclei of mass number 4, then

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a

3.3 MeV energy is absorbed

b

0.3 MeV of energy is released

c

2.81 MeV energy is absorbed

d

0.3 MeV of energy absorbed

answer is D.

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Detailed Solution

X3+Y5→2Z4+Q
∴Q=2×4×6.2−(3×5.3+5×7.4)
= 49.6–52.9 = –3.3MeV ∴3.3MeV absorbed

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