Q.

The binding energy of deuteron  12H is 1.112 MeV per nucleon and an α-particle He4 has a binding energy of 7.047 MeV per nucleon. Then in the fusion reaction  12H+12H24He+Q, the energy Q released is (in MeV)

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answer is 23.74.

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Detailed Solution

Q = 4(7.047) - 4(1.112) = 23.8 MeV

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