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Q.

The binding energy per nucleon for deuteron 1H2 and 2He4 are 1.1 MeV and 7MeV respectively. The energy released when two deuterons fuse to form a helium nucleus is

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a

1.1 MeV

b

23.6 MeV.

c

7 MeV

d

6MeV

answer is C.

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Detailed Solution

 1H2+1H2→2He4
For each  1H2→BE1=2(1.1)=2.2MeV
For  2He4→BE2=4(7)=28MeV
E = BE2 – 2BE1 = 28–2(2.2) = 23.6MeV

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The binding energy per nucleon for deuteron 1H2 and 2He4 are 1.1 MeV and 7MeV respectively. The energy released when two deuterons fuse to form a helium nucleus is