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Q.

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus, the energy released in the fusion is

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a

30.2 MeV

b

23.6 MeV

c

2.2 MeV

d

28.0 MeV

answer is B.

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Detailed Solution

Binding energy of two $H^{2}$ nuclei

= 2(1.1 x 2) = 4.4 MeV.

Binding energy of one ${He}^{4}$ nucelus

$= 4 \times 7.0 = 28 MeV$

:. Energy released $= 28 - 4 .4 = 23 .6 MeV$

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The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus, the energy released in the fusion is