Q.

The binding energy per nucleon of Li and He nuclei are 5.60 MeV and 7.06 MeV respectively. In the nuclear reaction given here the value of energy Q released is_______MeV

 37Li+11H24He+24He+Q

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a

18.9

b

15.26

c

3.24

d

17.28

answer is A.

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Detailed Solution

Binding energy of  37Li ,nucleus =7×5.60MeV=39.2MeV

Binding energy of  24He nucleus = 4×7.06MeV=28.24MeV

The reaction is  37Li+11H2 24He+Q

Q=2×28.24MeV39.2MeV=17.28MeV

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