The block of mass 3 kg which is at rest on a surface is pulled horizontally by a force. If the displacement of the block is 15 m in the first 3 s and the surface offers a resistance of 2 N. Find the sequence of steps to calculate the magnitude of applied force
(a) Note down the values of s, u, t and frictional force
(b) The applied force on the block is the sum of frictional force and net force.
(c) Substitute the values of s, u and t in the equation of motion and solve for ‘a’
(d) Using Newton’s second law of motion, calculate the net force acting on the block

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

a d b c

a c b d

a c d b

a b d c

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Given m = 3 kg
S = 15 m, t = 3s, u = 0
Frictional force
$\begin{array}{l} f_{f} = 2 N . (a) \\ 15 = 0 \times 3 + \frac{1}{2} \times a \times 3^{2} \\ a = \frac{10}{3} {ms}^{- 2} \end{array}$
$\begin{array}{l} F_{net} = ma = 3 \times \frac{10}{3} = 10 N \\ F_{a} = F_{net} + F_{f} = 10 + 2 = 12 N (b) \end{array}$