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The block of mass $M$ moving on the frictionless horizontal surface collides with the spring of spring constant $k$ and compresses it by length $L$ . The maximum momentum of the block after collision is

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zero

${ML}^{2} / k$

$\frac{{kL}^{2}}{2 M}$

$\sqrt{Mk} L$

answer is C.

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Detailed Solution

$\frac{1}{2} {kL}^{2} = \frac{P^{2}}{2 M}$

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