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Q.

The bob of a pendulum is released from a horizontal position A as shown in fig. If the length of the pendulum is 2m and 10% of the initial energy of the bob is dissipated as heat due to the friction of air, what would be the speed of the bob when it reaches the lowermost point B? take g =10ms^-2.

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a

3ms^-1

b

4ms^-1

c

5ms^-1

d

6ms^-1

answer is D.

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Detailed Solution

Given 10% of the initial energy is lost.

That means 90% of the potential energy is converted to kinetic energy.

$\frac{90}{100} mgh = \frac{1}{2} {mv}^{2}$

$\Rightarrow v = \sqrt{1.8 gh} = 6 m / s$

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The bob of a pendulum is released from a horizontal position A as shown in fig. If the length of the pendulum is 2m and 10% of the initial energy of the bob is dissipated as heat due to the friction of air, what would be the speed of the bob when it reaches the lowermost point B? take g =10ms-2.