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The bob P of a simple pendulum of length L released from 60^o to the vertical hits the bob Q of another pendulum of same length which is at rest on a smooth table top as shown in figure. If the masses of P and Q are same and collision is elastic, then the height to which the bob Q rises after collision is (neglect the sizes of the bobs)

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zero

$\frac{L}{2}$

$\frac{L}{4}$

$\frac{L}{8}$

answer is A.

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Detailed Solution

As the collision is elastic and masses are equal then it will go to the same height

$h = L (1 - \cos θ) = L / 2$

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